Could someone help me with this physics problem?

[Sara Micelli]

t=f times the square root of a divided by b Solve for b.

I know this should be easy for me but I'm stuck on it for some reason. Thanks for any help.

[¤I Love Clay Aiken¤]

And this... would be the reason why I got C's and D's in Physics. And F's.:o I never understood all the A's and B's etc.. it would be so much easier if it were an actual example.

[Sara Micelli]

Originally posted by ¤MsConanOBrien¤
And this... would be the reason why I got C's and D's in Physics. And F's.:o I never understood all the A's and B's etc.. it would be so much easier if it were an actual example.

I know what you mean. I'm usually pretty good at these but this problem has me stumped for some reason.

[Swimfan85]

ha physics sucked but I had a good class so what can I say...but lemme try

wouldnt you want to get B to the other side, you do that by multplying it on each side, so it cancles out on the one side it was one so now you have an equation that looks like

B x T = F x square root of A

then wouldnt you want to get B alone, so you u divide both sides by T, and it cancles out on the side its on so now you have

B = F x square root of A divided T

[BrandonS]

Originally posted by Swimfan85
ha physics sucked but I had a good class so what can I say...but lemme try

wouldnt you want to get B to the other side, you do that by multplying it on each side, so it cancles out on the one side it was one so now you have an equation that looks like

B x T = F x square root of A

then wouldnt you want to get B alone, so you u divide both sides by T, and it cancles out on the side its on so now you have

B = F x square root of A divided T
This is correct if the B was not under the square root sign, which was not clear in the statement of the problem. To state the problem unambiguously, being unable really to show equations here, you need parentheses.

[Mijada]

You guys have me stumped. I never even got past Algebra II.:lol:

[BrandonS]

Originally posted by Mijada
You guys have me stumped. I never even got past Algebra II.:lol:
Up to this point, this is only algebra.

[Mijada]

Originally posted by BrandonS
Up to this point, this is only algebra.

Really? I never remember having problems like that in Algebra I or II.

[BrandonS]

Originally posted by Mijada
Really? I never remember having problems like that in Algebra I or II.
You have one variable equal to the product and quotient of some other variables, with some under a square root sign. You just have to keep multiplying, dividing, and possibly squaring (if the b is under the radical too, which wasn't clear) until you have isolated the variable you are trying to solve for:

example: a = bc/d solve for c

ad = bc

c = ad/b

No physics is involved in just untangling an equation.

[Kay Scarpetta]

Ick.. I hated Algebra so much.

[Sara Micelli]

Thanks for all of your help. My teacher helped me understand it and I feel really dumb now lol. I'm sorry that the question was vague. It was hard explain over the computer.

[BrandonS]

Originally posted by popcornperson2002
Thanks for all of your help. My teacher helped me understand it and I feel really dumb now lol. I'm sorry that the question was vague. It was hard explain over the computer.
Glad you have a good teacher, who can explain the material well.